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#### \( x^3 - 2x^2 + x + C \) - Veritas Home Health

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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z = c \sin(\phi) \cos(\phi)
Now compute \(x^2 + y^2\):
x^2 + y^2 = c^2 \sin^4(\phi) (\cos^2 heta + \sin^2 heta) = c^2 \sin^4(...
From the identity \(\sin^2(\phi) = rac{
ho^2}{c^2}\), but express \(x^2 + y^2\) in terms of \(z\):
z = c \sin\phi \cos\phi = rac{c}{2} \sin(2\phi)
But use identity:
z =
ho \cos\phi = c \sin\phi \cos\phi = rac{c}{2} \sin(2\phi)
Alternatively, use:

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