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📅 March 1, 2026 👤 scraface

Mar 01, 2026

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We are given $ f(1) = 1 $, so:
f(2) + f(0) = 4 \quad \text{(1)}
Now plug in $ a = 0, b = 1 $:
f(1) + f(-1) = 2f(0) + 2f(1) \Rightarrow 1 + f(-1) = 2f(0) + 2 \Righta...
Now plug in $ a = 1, b = 0 $:
f(1) + f(1) = 2f(1) + 2f(0) \Rightarrow 2 = 2 + 2f(0) \Rightarrow f(0)...
Substitute $ f(0) = 0 $ into equation (1):
f(2) + 0 = 4 \Rightarrow f(2) = \boxed{4}
Question: Find the area enclosed by the graph of $ |x| + |y| = 4 $.
Solution: The equation $ |x| + |y| = 4 $ represents a diamond (rhombus...

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