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Home » $ 6(-\frac143) + b = 5 \Rightarrow -28 + b = 5 \Rightarrow b = 33 $ - Veritas Home Health

$ 6(-\frac143) + b = 5 \Rightarrow -28 + b = 5 \Rightarrow b = 33 $ - Veritas Home Health

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 \[ 3n^2 + 2 = 425 \]

📌 \[ 3n^2 = 423 \]

📌 \[ n^2 = 141 \]

📌 \[ n = \sqrt{141} \approx 11.87 \]

📌 Wait — 141 is not a perfect square. Try checking if the middle term is \( n \), so use:

📌 Let the middle integer be \( n \), then:

📌 \[ 3n^2 + 2 = 425 \Rightarrow 3n^2 = 423 \Rightarrow n^2 = 141 \Rightarrow n = \sqrt{141} \]

📌 But 141 is not a perfect square — check if 137, 138, etc., work. Try actual integers.

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Subtracting equations:
$ 7a + 3b + c = 8 $
$ 19a + 5b + c = 16 $
$ 37a + 7b + c = 34 $
Subtracting these:
$ 18a + 2b = 18 $ → $ 9a + b = 9 $
Subtracting: $ 3a = 5 $ → $ a = \frac{5}{3} $, $ b = -6 $. Then $ c =...
g(x) = \dfrac{5}{3}x^3 - 6x^2 + \dfrac{43}{3}x - 15.
Substitute $ x^2 - 1 $:
g(x^2 - 1) = \dfrac{5}{3}(x^2 - 1)^3 - 6(x^2 - 1)^2 + \dfrac{43}{3}(x^...

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