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Home » \( b^2 + 64 = 100 \) - Veritas Home Health

\( b^2 + 64 = 100 \) - Veritas Home Health

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Now, substitute $ y = x^2 + 1 $ to find $ g(x^2 + 1) $:
g(x^2 + 1) = 2(x^2 + 1)^2 - (x^2 + 1) - 2 = 2x^4 + 4x^2 + 2 - x^2 - 1...
The final answer is $ \boxed{2x^4 + 3x^2 - 1} $.
Question: An angel investor analyzes a medical startup's growth, model...
Solution: Let $ y = x^2 + 2 $. Then $ x^2 = y - 2 $. Express $ g(y) $...
g(y) = 3x^6 - 4x^4 + 5x^2 - 2 = 3(x^2)^3 - 4(x^2)^2 + 5x^2 - 2 = 3(y -...
3(y^3 - 6y^2 + 12y - 8) - 4(y^2 - 4y + 4) + 5y - 10 - 2 = 3y^3 - 18y^2...
Thus, $ g(x^2 - 2) = 3(x^2 - 2)^3 - 22(x^2 - 2)^2 + 57(x^2 - 2) - 52 $...
3(x^6 - 6x^4 + 12x^2 - 8) - 22(x^4 - 4x^2 + 4) + 57x^2 - 114 - 52 = 3x...
The final answer is $ \boxed{3x^6 - 40x^4 + 181x^2 - 278} $.

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