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📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Simplify inside the square root:
x = \frac{4 \pm \sqrt{16 + 48}}{4}
x = \frac{4 \pm \sqrt{64}}{4}
x = \frac{4 \pm 8}{4}
The roots are:
x = \frac{4 + 8}{4} = 3 \quad \text{and} \quad x = \frac{4 - 8}{4} = -...
If \(f(x) = 3x^2 - 2x + 1\) and \(g(x) = x - 4\), find \(f(g(2))\).
First, calculate \(g(2)\):
g(2) = 2 - 4 = -2
Next, substitute into \(f(x)\):

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