Other terms match. Thus, $ h(x) = rac12x^2 + bx $. Verify that $ h(x + y) = rac12(x + y)^2 + b(x + y) = rac12x^2 + xy + rac12y^2 + bx + by $, which equals $ h(x) + h(y) + xy $. The general solution is $ h(x) = rac12x^2 + bx $, where $ b $ is a constant. The function is $ oxedh(x) = rac12x^2 + bx $.1. - Veritas Home Health