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Home » PS5 30th Anniversary Edition: Is This the Ultimate Collector’s Dream? Find Out! - Veritas Home Health

PS5 30th Anniversary Edition: Is This the Ultimate Collector’s Dream? Find Out! - Veritas Home Health

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 11Ã16=176 â 1+7+6=14 â no

📌 11Ã17=187 â 1+8+7=16 â no

📌 11Ã18=198 â 1+9+8=18 â divisible by 9 â yes

📌 So the smallest multiple of 11 in [100,199] divisible by 9 is 198.

📌 Therefore, the smallest possible batch size that allows full utilization (i.e., divides a valid dataset size) is $ oxed{198} $.

📌 But wait: the model can use any multiple of 9, not necessarily including 11. The batch size $ B $ must be such that some valid dataset (divisible by 9, â¥100, <200) can be divided into batches of size $ B $. Since $ B $ must divide the dataset size, $ B $ must divide some multiple of 9 in [100,199].

📌 But any integer $ B $ divides some multiple of 9 (e.g., take $ D = B \cdot 9 $, but again, $ B $ must be divisible by 11).

📌 But the condition is not that $ B $ divides $ D $, but that $ D $ is a multiple of 9 and $ B $ divides $ D $ â so $ B $ must be a divisor of some multiple of 9.

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h(3) = 27 + 3p + q = 24 \quad ext{(3)}
p + q = 3 \quad ext{(i)}
From (2):
2p + q = 2 \quad ext{(ii)}
+ q = 3 \Rightarrow q = 4
Now verify with (3):
h(3) = 27 + 3(-1) + 4 = 27 - 3 + 4 = 28
e 24
Contradiction! So our assumption that \( h(x) = x^3 + px + q \) (missi...
Wait â perhaps \( h(x) = x^3 + px + q \), but we must use all three...

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