Solution: Let $ a + b = 10 $ and $ a^2 + b^2 = 58 $. Compute $ (a + b)^2 = 100 = a^2 + 2ab + b^2 = 58 + 2ab $. Solve for $ ab $: $ 2ab = 42 \Rightarrow ab = 21 $. The area is $ \frac12ab = \boxed\frac212 $. - Veritas Home Health