Solution: The dot product of two unit vectors is $\mathbfu \cdot \mathbfv = \cos\theta$. Given $\cos\theta = \frac\sqrt32$, the angle $\theta$ satisfies $\theta = \arccos\left(\frac\sqrt32\right)$. This corresponds to $\theta = 30^\circ$ or $\frac\pi6$ radians. However, since cosine is positive in both the first and fourth quadrants, but angles between vectors are typically taken in $[0, \pi]$, the solution is $\boxed\dfrac\pi6$. - Veritas Home Health