Solution: The magnitude of the cross product is $\|\mathbfp \times \mathbfq\| = \|\mathbfp\| \|\mathbfq\| \sin\theta$. Since $\mathbfp$ and $\mathbfq$ are unit vectors, $\|\mathbfp \times \mathbfq\| = \sin\theta = \frac12$. Thus, $\theta = \arcsin\left(\frac12\right)$, which gives $\theta = \frac\pi6$ or $\frac5\pi6$. However, the angle between vectors is taken as the acute angle, so $\theta = \boxed\dfrac\pi6$. - Veritas Home Health