Solution: The product of $ k $ consecutive integers is divisible by $ k! $. For five consecutive integers, this is $ 5! = 120 $. For example, $ 1 \cdot 2 \cdot 3 \cdot 4 \cdot 5 = 120 $, and $ 2 \cdot 3 \cdot 4 \cdot 5 \cdot 6 = - Veritas Home Health