Solution: The volume of the cylinder is $ V_\textcyl = \pi r^2 (6r) = 6\pi r^3 $. The volume of the cone is $ V_\textcone = \frac13 \pi (2r)^2 (3r) = \frac13 \pi (4r^2)(3r) = 4\pi r^3 $. The ratio is: - Veritas Home Health