The period of the function is \( \frac2\pib \). Since \( f\left(\frac\pi2b\right) = 4 \), it indicates a quarter-period shift, consistent with \( b \) being arbitrary for simplicity. Assume one full cycle completes in \( \frac2\pib = 2\pi \), giving \( b = 1 \). - Veritas Home Health