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Home » This Salute Meme Is Spreading Fast—Watch How EVERYONE’s Joining the Fun! - Veritas Home Health

This Salute Meme Is Spreading Fast—Watch How EVERYONE’s Joining the Fun! - Veritas Home Health

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 So total favorable: $4 \times 3 \times 12 = 144$ — same as before.

📌 So yes, 144 favorable.

📌 Total: $4^4 = 256$

📌 So probability: $ \frac{144}{256} = \frac{9}{16} $? Wait: $144 \div 16 = 9$, $256 \div 16 = 16$, so $ \frac{9}{16} $ — but $ \frac{144}{256} = \frac{54}{96} = \frac{27}{48} = \frac{9}{16} $, yes.

📌 But $ \frac{144}{256} = \frac{9}{16} $? $144 \div 16 = 9$, $256 \div 16 = 16$, but $16 \times 16 = 256$, $16 \times 9 = 144$, yes. But $ \frac{144}{256} = \frac{144 \div 16}{256 \div 16} = \frac{9}{16} $, correct.

📌 But $ \frac{9}{16} $ is greater than 0.5, but is it reasonable? Let’s compute total number of distinct patterns.

📌 Alternatively, use known results: the number of sequences of length 4 over 4 symbols with one symbol appearing twice, two others once, one absent: standard.

📌 Yes, correct.

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x^4 = (x^2)^2 = (u - 1)^2 = u^2 - 2u + 1
x^4 + 2x^2 + 2 = (u^2 - 2u + 1) + 2(u - 1) + 2
u^2 - 2u + 1 + 2u - 2 + 2 = u^2 + 1
Now, substitute $ x^2 - 1 $ into $ g $:
g(x^2 - 1) = (x^2 - 1)^2 + 1 = x^4 - 2x^2 + 1 + 1 = x^4 - 2x^2 + 2
Thus, the answer is:
\boxed{x^4 - 2x^2 + 2}
Question: Find the remainder when $ u^3 + 2 $ is divided by $ u + 1 $.
We use the **Remainder Theorem**:
The remainder when a polynomial $ f(u) $ is divided by $ u - c $ is $...

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