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Home » where \(\gamma = rac1\sqrt1-v^2\). - Veritas Home Health

where \(\gamma = rac1\sqrt1-v^2\). - Veritas Home Health

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 D) False — although $ r s = \frac{ab}{2} $, the statement area equals $ r \cdot s $ is analytically true only when $ r $ is inradius, which it is — so D is misleading.

📌 C) False — the identity $ A = r s $ is valid only if $ r $ is the inradius, which it is, so C is incorrect.

📌 Wait: $ A = r s $ is always true for inradius $ r $. So area is $ r s $ by definition when $ r $ is inradius.

📌 So the statement the area of the circle over the area of the triangle depends, but here: the area of the triangle is $ r \times s $ — yes, this is correct.

📌 So correct claim is proven. Best choice:

📌 A) True, by definition — correct.

📌 Because in any triangle, the area is $ A = r \cdot s $, where $ s $ is semiperimeter and $ r $ is inradius. This holds for right triangles as well.

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P = 6 \times s = 6 \times 12 = 72 \text{ cm}
So, the perimeter of the hexagon is:
\boxed{72 \text{ cm}}
Problem 3:
A cone has a base radius of 5 cm and a slant height of 13 cm. What is...
The total surface area \(A\) of a cone is the sum of the base area and...
A = \pi r^2 + \pi r l
\(r = 5\) cm (radius),
\(l = 13\) cm (slant height),
\(\pi \approx 3.14\)

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