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📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Let each animation being accepted be a Bernoulli trial with success pr...
We want the probability that **fewer than two** animations are accepte...
Let $ X \sim \text{Binomial}(3, 0.75) $.
P(X < 2) = P(X = 0) + P(X = 1)
$ P(X = 0) = \binom{3}{0} (0.75)^0 (0.25)^3 = 1 \cdot 1 \cdot 0.015625...
$ P(X = 1) = \binom{3}{1} (0.75)^1 (0.25)^2 = 3 \cdot 0.75 \cdot 0.062...
Add:
P(X < 2) = 0.015625 + 0.140625 = 0.15625
Thus, the probability that fewer than two animations are accepted is:
\boxed{0.15625}

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